Question

Find the probability of a non leap year selected at random with 53 sundays

Answer 1

no. of weeks in a non leap year is

$= 367 \div 7 = 52.14$

there are 52 weeks and 1 day in a non leap year.

The one day can be any of the 7 days of the week.

P(53 sundays in non leap year) is 1/7

Answer 2

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Correct option: (C)

A non-leap year has 365 days.

365 days = 52 weeks + 1 day

Since 52 weeks = 52 x 7 = 364 days

Hence there will be 52 Sundays in a year.

This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, or Sunday.

Out of these total 7 outcomes, the number of favourable outcomes is 1.

Hence, the probability of getting 53 Sundays = 1 / 7

Hope it's Helpful.....:)