Question

Find the probability of a throwing a total of 8 in a single throw with two dice

Answer 1

Answer:

5/36

Solution:

Total number of outcomes = 6 × 6 = 36

Here,

A total of 8 is the favourable outcome.

Thus,

Favourable outcomes are :

{ (2,6) , (3,5) , (4,4) , (5,3) , (6,2) }

Here,

The number of favourable outcomes is 5 .

Also,

We know that ,

no. of favourable outcomes

Probability = ––––––––––·––––·–––·–––

Total no. of outcomes

Thus,

Here, the probability of getting a total of 8 will be;

no. of favourable outcomes

Probability = –––––––––––·––––·–––·––

Total no. of outcomes

=> P = 5/36

Hence,

The required probability is 5/36 .

Answer 2

Answer:

5/36

Step-by-step explanation:

total outcomes=36

sum of getting eigth=5

so,probability of event=5/36