Question

Find the probability of describing a single
event for the given condition
James speaks 70% truth and Williams
speaks 90% truth.​

Answer 1

Answer:

probability of 1st condition

favorable condition = 70% =70

total = 100 % = 100

so

p = 70/100

= 7/10

in second condition

Williams

favorable condition = 90

total = 100

so

p = 90 / 100

p= 9/10

Answer 2

The probability of single event for the given condition is 0.66

Step-by-step explanation:

Given:

• James speaks 70% truth
• Williams speaks 90% truth.​

To find: Probability of single event for the given condition

Solution

Let $T_{1} =$ james speak the truth

Let $T_{2} =$ Williams speak truth

$P(T_{1} ) = \frac{70}{100} = \frac{7}{10}$

$P(T_{2} ) = \frac{90}{100} = \frac{9}{10}$

$P(|T_{1} |) = (1 - \frac{7}{10} )$

= $\frac{3}{10}$

$P(|T_{2} |) = (1 - \frac{9}{10})$

= $\frac{1}{10}$

⇒ P[($T_{1}$ ∩ $T_{2}$)   + P [($P(|T_{1} |)$ ∩ $P(|T_{2} |)$

⇒ $P(T_{1} ) .P(T_{2} ) + P(|T_{1}| ).P(|T_{2}|)$

= ($(\frac{7}{10} .\frac{9}{10} ) + (\frac{3}{10} .\frac{1}{10} )$

=$\frac{63}{100} + \frac{3}{100}$

= $\frac{66}{100}$

=0.66

Final answer:

The probability of single event for the given condition is 0.66

#SPJ3