find the probability of following events when three coins are tossed.
(i) getting at least two heads.
(ii) Getting no head.
Answers
Answered by
0
the probability is the 1 one
Adityakale:
how you solve it?
Answered by
2
Sample space - HHH, HHT, HTH, THH, TTT, HTT, THT, TTH
1- P( getting at least 2 heads) =4/8 =1/2
2- P ( getting no head) =1/8
1- P( getting at least 2 heads) =4/8 =1/2
2- P ( getting no head) =1/8
Similar questions