Question

find the probability of getting 1-50( including 1 and 50)number when a number is drawn 1)both tens and units digit are same 2)prime number​

Answer 1

☯ AnSwEr

(1).

Total outcomes = 50 (because there are total 50 numbers from 1 to 50).

Favourable outcomes = 4 (because there are only four numbers from 1 to 50 i.e.11,22,33,44)

We know that,

$\small{\star{\boxed{\boxed{\sf{Probablity = \dfrac{Favourable \: outcomes}{Total \: outcomes} }}}}}$

★ Putting Values ★

$\sf{\dashrightarrow Probablity = \dfrac{\cancel{4}}{\cancel{50}}} \\ \\ \sf{\dashrightarrow Probability = \dfrac{2}{25}} \\ \\ \Large{\implies{\boxed{\boxed{\sf{Probablity = \dfrac{2}{25} }}}}} \\ \\ \sf{\underline{\therefore \: \dfrac{2}{25} \: is \: correct \: answer}}$

$\rule{200}{2}$

We know that,

$\small{\star{\boxed{\boxed{\sf{Probablity = \dfrac{Favourable \: outcomes}{Total \: outcomes} }}}}}$

Where,

Total outcomes = 50 (because there are total 50 numbers from 1 to 50).

Favorable outcomes = 15 (because there are 15 prime numbers from 1 to 50 I.e, 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47).

★ Putting Values ★

$\sf{\dashrightarrow Probablity = \dfrac{\cancel{15}}{\cancel{50}}} \\ \\ \sf{\dashrightarrow Probability = \dfrac{3}{10}} \\ \\ \Large{\implies{\boxed{\boxed{\sf{Probablity = \dfrac{3}{10} }}}}} \\ \\ \sf{\underline{\therefore \: \dfrac{3}{10} \: is \: correct \: answer}}$