find the probability of getting 53 Fridays 53 Saturdays 53 Friday or 53 Saturday in a leap year
Answers
Answered by
0
8hh and then you should receive your area to do a great
Answered by
9
52×7=364 and for a leap year it's 366
The probability that a leap year selected at random will contain either 53 Fridays or 53 Saturdays = n(E)/n(S)
= 2/7
Similar questions