find the probability of getting 53 fridays in a leap year
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A leap year consists of 366 days i.e. 52 weeks and 2 days remaining.
These 2 days be any of the following.
(Monday, Tuesday) (Tuesday,Wednesday) (Wednesday, Thursday) (Thursday, Friday) (Friday, Saturday) (Saturday,Sunday)
The number of cases=7
The number of cases in which we get Friday=2
The probability of getting 53 Friday= 2/7
Hope it helps u....
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