Find the probability of getting 53 fridays in a leap year ?
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Answered by
5
leap year consists of 366 days 364 days mean 52 weeks which mean 52 fridays +2 days are extra there are seven posibble outcomes for these two days mon,tues
tues,wed
wed,thurs
thurs,fri
fri,sat
sat,sun
sun,mon
so probability for 53 fridys in leap year is 2/7
tues,wed
wed,thurs
thurs,fri
fri,sat
sat,sun
sun,mon
so probability for 53 fridys in leap year is 2/7
Answered by
7
A leap year consists of 366 days i.e 52 weeks + 2 days remaining.
These 2-days can be
{Mon,Tue},{Tue,Wed},{Wed,Thu},{Thu,Fri},{Fri,Sat},{Sat,Sun},{Sun,Mon}.
The total number of cases = 7.
The number of cases in which we get a Friday = 2{Thu, Fri},{Fri, Sat}.
Therefore the required probability of getting 53 Fridays in a leap year = 2/7.
Hope this helps!
These 2-days can be
{Mon,Tue},{Tue,Wed},{Wed,Thu},{Thu,Fri},{Fri,Sat},{Sat,Sun},{Sun,Mon}.
The total number of cases = 7.
The number of cases in which we get a Friday = 2{Thu, Fri},{Fri, Sat}.
Therefore the required probability of getting 53 Fridays in a leap year = 2/7.
Hope this helps!
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