Question

Find the probability of getting 53 fridays in a non-leap year.

Answer 1

1/7 is the probability of getting 53 fridays in a non-leap year

Solution:

The non-leap year has 52 weeks and 1 day

So,we have 52 weeks + 1 day

In 52 weeks, we have 52 fridays

Now considering the 1 day,

1 day can be any day of 7 days of week, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday

Therefore,

$\text{ Probability of 1 Odd day to be Friday } = \frac{1}{7}$

Thus 1/7 is the probability of getting 53 fridays in a non-leap year

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Answer 2

Answer:

1/7 is the probability