Math, asked by zozpsdkdosp, 8 months ago

Find the probability of getting 53 saturdays in a leap year... ​

Answers

Answered by shaheenah08
2

Answer:

Possible events for 2 odd days

The odd day may be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday or Saturday. Therefore, the total number of possible outcome or elements of sample space is 7.

Probability of 2 Odd day to be Saturday :

The elements of sample space for 2 odd days

S = {Saturday & Sunday, Sunday & Monday, Monday & Tuesday, Tuesday & Wednesday, Wednesday & Thursday, Thursday & Friday, Friday & Saturday}

The elements of expected events

A = {{Friday & Saturday}, {Saturday & Sunday}}

P(A) =S

A

={{Friday & Saturday}, {Saturday & Sunday}}

{Saturday & Sunday, . . . , Friday & Saturday}

P(A) = 2/7

P(A) = 0.28

0.28 or 2/7 is probability for 53 Saturdays in a leap year.

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Answered by Anonymous
2

the probability of getting 53 Saturdays in a leap year is 2/7

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