Question

find the probability of getting 53 Sunday in a leap year.​

Answer 1

Answer:

$\frac{2}{7}$

Explanation:

In leap year there are two more extra days (52 each day , 52 × 7 = 364 ) .

So they can be

Sun-Mon , Mon-Tue , .....,Sat-Sun

In those 7 cases 2 includes Sunday .

Answer 2

Answer:

We know that there are 366days in a leap year = 52 weaks +2 days

These 2 days can be :

1. {Sun, Mon}

2. {Mon, Tues}

3. {Tues, Wed}

4. {Wed, Thurs}

5. {Thurs, Fri}

6. {Fri, sat}

7. {Sat, sun}

N(s) = 7.

Now,

Out of these 7 outcomes, the favorable outcomes are 2. (Sun, mon), (sat, sun).

N(a) = 2.

Therefore the required probability p(A) =N(a)/ N(s)

=2/7.

Hope this helps!