Question

find the probability of getting 53 Sundays in a leap year
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Answer 1

Answer:

53/360 is the probability of getting 53 Sundays in a leap year .

Answer 2

Answer:

1. Therefore the probability of a year having 53 Sundays = n(E)/n(S) = 1/7. If the year in question is a leap year, there are 366 days. Since 364 is a multiple of 7, there will be 52 Sundays, 52 Mondays,…………….53 Saturdays.
2. So altogether for the Gregorian calendar system, the probability of any given leap year being a leap year with 53 Sundays and 53 Mondays is 15/97 = 15.46…%, which is a little different from our earlier estimate of 1/7 = 14.29…%.
3. 53 Sundays
4. What is the probability that a leap year has 53 Sundays? There are 366 days in a leap year, i.e, 1 more than a normal year. That means that we already have 52 sundays for sure

Step-by-step explanation:

1 year = 365 days

A leap year has 366 days

A year has 52 weeks. Hence there will be 52 Sundays for sure.

52 weeks = 52 x 7 = 364 days

366 – 364 =2 days

In a leap year there will be 52 Sundays and 2 days will be left.

These 2 days can be

Sunday, Monday

Monday, Tuesday

Tuesday, Wednesday

Wednesday, Thursday

Thursday, Friday

Friday, Saturday

Of these total 7 outcomes, the favourable outcomes are 2.

Hence the probability of getting 53 days

=2/7

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