Question

find the probability of getting 53 sundays in a leap year...........

Answer 1

Total number of days in a leap year = 366

Dividing 366 by 7 , we have quotient as 52 and 2 as a remainder.

Now, 52 sundays are fixed.

So, the outcomes for 53rd sunday will be calculated as:-

Now, these two days can be as :-

(Sunday, monday) ;

(Monday,tuesday) ;

(tuesday,wednesday) ;

(wednesday,thursday);

(Thursday,friday) ;

(friday,saturday) ; and

(Saturday,sunday)

Now, we have total number of outcomes = 7 .

Number of favourable outcomes = 2 (Sunday, monday) and (saturday,sunday)

$\underline{ \bf{probability(sunday \: in \: leap \: year)}}$

$= \boxed{ \bf{ \frac{favorable \: outcomes}{total \: number \: of \: outcomes} }}$

$= \bf{\frac{2}{7} }$

______________________________

$\boxed{ \bf{note}}$

Probability can never be smaller than 0 .

It can also never be greater than 1 .

Answer 2

Answer:2/7

Step-by-step explanation: