Math, asked by mailforsarah786, 5 months ago

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Find the probability of getting 53 Sundays in a leap year.

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Answers

Answered by TheDeadlyWasp
4

Step-by-step explanation:

In 365 days,

Number of weeks = 52 weeks and 1 day is remaining.

1 remaining day can be (Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday).

Total of 7 outcomes,

the favourable outcome is 1.

∴ probability of getting 53 Sundays = 1 / 7.

Hope it helps...

Answered by 10Saffron
2

Find the probability of getting 53 Sundays in a leap year.

Non-leap year = 365 days

In 365 days, Number of weeks = 52 weeks and 1 day is remaining.

For 52 weeks number of Sundays = 52

1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.

Total of 7 outcomes, the favourable outcome is 1.

∴ probability of getting 53 Sundays = 1 / 7.

hope it helps u

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