Find the probability of getting 53 sundays in a non leap year. (1) 2/7 (2) 1/7 (3) 1/5 (4) 1/9
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Answered by
3
Answer: (2) 1/7
Non-leap year = 365 days
In 365 days, Number of weeks = 52 weeks and 1 day is remaining.
For 52 weeks number of Sundays = 52
1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
Total of 7 outcomes, the favourable outcome is 1.
∴ probability of getting 53 Sundays = 1 / 7.
Answered by
6
Answer:
1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Total of 7 outcomes, the favourable outcome is 1. ∴ probability of getting 53 Sundays = 1 / 7.
Step-by-step explanation:
Hope it was helpful
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