Math, asked by khushi02022010, 7 months ago

Find the probability of getting 53 sundays in a non leap year. (1) 2/7 (2) 1/7 (3) 1/5 (4) 1/9​

Answers

Answered by Anonymous
3

Answer: (2) 1/7

Non-leap year = 365 days

In 365 days, Number of weeks = 52 weeks and 1 day is remaining.

For 52 weeks number of Sundays = 52

1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.

Total of 7 outcomes, the favourable outcome is 1.

∴ probability of getting 53 Sundays = 1 / 7.

Answered by LastShinobi
6

Answer:

1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Total of 7 outcomes, the favourable outcome is 1. ∴ probability of getting 53 Sundays = 1 / 7.

Step-by-step explanation:

Hope it was helpful

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