find the probability of getting 53 Sundays in a non leap year
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this is a right answer because number of possible outcome upon number of Total outcome is the formula of probability
this is a right answer because number of possible outcome upon number of Total outcome is the formula of probability
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A leap year has 366 days
therefore 52 weeks, i.e. 52 Sunday and 2 days.
The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday.
For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday.
-->n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
therefore 52 weeks, i.e. 52 Sunday and 2 days.
The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday.
For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday.
-->n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
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