find the probability of getting 53 Sundays in a non leap year...
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the probability of getting 53 Sunday are
no.of favourable outcomes / total no.of outcome
53/365
no.of favourable outcomes / total no.of outcome
53/365
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2
Answer:
We know that A non-leap year consists of 365 days.
In 365 days, Number of weeks = 52 and 1 day remaining.
For 52 weeks, There will be 52 Sundays.The remaining 1 day can be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday.
Out of these 7 total outcomes, the favorable outcomes are 1.
Hence the probability of getting 53 Sundays = 1/7.
Hope this helps!
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