find the probability of getting 53 Sundays in a year which is not leap year
Answers
Answered by
1
Step-by-step explanation:
In 365 days, Number of weeks = 52 weeks and 1 day is remaining.
1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
Total of 7 outcomes, the favourable outcome is 1. ∴ probability of getting 53 Sundays = 1 / 7.
Answered by
0
Step-by-step explanation:
oo Arif ln 73₹)++#473)+736"?!+5#74gswivdwj
Similar questions