Question

Find the probability of getting 53 Wednesday in leap year

Answer 1

Step-by-step explanation:

In a leap year there will be 52 Wednesdays and 2 days will be left. Of these total 7 outcomes, the favourable outcomes are 2. Hence the probability of getting 53 Wednesdays in a leap year = 2/7..

Answer 2

Answer:

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Step-by-step explanation:

Let P(E) be the event of probability of getting 53 wednesdays

A leap year consist of 366 days

365 = 52 × 7= 364 days and 2  days left from the complete weeks

This two days can be (Sun, Mon), (Mon, Tue), (Tue, Wed), (Wed,Thu), (Thu, Fri) (Fri,Sat) and (Sat, Sun)

Out of these 7 pairs, 2 of them have wednesday

So, number of favourable outcome to the event P(E) = 2

Total outcomes = 7

The probability of getting 53 mondays= 2/ 7

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