Find the probability of getting 53 Wednesday in leap year
Answers
Step-by-step explanation:
In a leap year there will be 52 Wednesdays and 2 days will be left. Of these total 7 outcomes, the favourable outcomes are 2. Hence the probability of getting 53 Wednesdays in a leap year = 2/7..
Answer:
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Step-by-step explanation:
Let P(E) be the event of probability of getting 53 wednesdays
A leap year consist of 366 days
365 = 52 × 7= 364 days and 2 days left from the complete weeks
This two days can be (Sun, Mon), (Mon, Tue), (Tue, Wed), (Wed,Thu), (Thu, Fri) (Fri,Sat) and (Sat, Sun)
Out of these 7 pairs, 2 of them have wednesday
So, number of favourable outcome to the event P(E) = 2
Total outcomes = 7
The probability of getting 53 mondays= 2/ 7
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