Find the probability of getting 55 Fridays in a leap year.
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Answer:
The number of cases in which we get a Friday = 2. The probability of getting 53 Fridays in a leap year = 2/7.
Step-by-step explanation:
A leap year has 366 days or 52 weeks and 2 odd days. The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}. So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays is 2/7.
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