Find the probability of getting 9,7 and 6 when two dice are thrown
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Probability of getting 9=(3,6),(6,3),(4,5),(5,4)=4outcomes
Probability of getting 7=(1,6),(6,1),(2,5),(5,2),(3,4),(4,3)=6 outcomes
Probability of getting 6=(1,5),(5,1),(2,4),(4,2),(3,3)=5outcomes
total favourable outcomes=15
total possible outcomes=6×6=36
probability of getting favourable outcomes=15/36
which is equal to 5/12
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