Math, asked by konica833, 3 months ago

find the probability of getting a doublet in a throw of a pair of dice​

Answers

Answered by Anonymous
4

Step-by-step explanation:

There are six ways to roll 2 dice such that both dice have the same value

These are the outcomes (1,1),(2,2),(3,3),(4,4,)(5,5) and (6,6).

To find the total number of outcomes, note that there are 6 choices for the first die (values 1–6) and there are 6 choices for the second die (again values 1–6) and so by the Multiplication Principle (MP) there are 36 total outcomes from rolling two dice once.

Now we have the following:

P(getting a doublet) =

Total number of outcomes

Number of ways to get double

=

36

6

=

6

1

Thus, the probability of getting a doublet is

6

1

.

Answered by Kenaz
1

Step-by-step explanation:

There are six ways to roll 2 dice such that both dice have the same value

These are the outcomes (1,1),(2,2),(3,3),(4,4,)(5,5) and (6,6).

To find the total number of outcomes, note that there are 6 choices for the first die (values 1–6) and there are 6 choices for the second die (again values 1–6) and so by the Multiplication Principle (MP) there are 36 total outcomes from rolling two dice once.

Now we have the following:

P(getting a doublet) =

Total number of outcomes

Number of ways to get double

= 36/6

= 1/6

Thus, the probability of getting a doublet is 61

.


sumitverma5479: 6/36 = 1/6 ans
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