find the probability of getting a multiple of 2 or 3 when a die is thrown
should 6 be included once or twice?
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Step-by-step explanation:
P(multiple of 2 or multiple of 3) = P(2) + P(3) + P(4) + P(6) =
1/6 + 1/6 + 1/6 + 1/6 = 4/6 = 2/3.
6 should be included once.
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