Question

find the probability of getting a number between 1 and 100 which is divisible by 1 and itself only.

Answer 1

100 is the possibility

Answer 2

The probability is 0.25

Step-by-step explanation:

Any number which is divisible by 1 and itself is called a prime number.

1 is neither prime nor composite so 1 is not considered here.

Prime numbers between 1 and 100 are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97

25 prime numbers are there in between 1 and 100.

Total numbers are 100 from 1 to 100.

Finding Probability is to check the feasibility of a particular situation.

$\text{Probability}=\frac{\text { Number of feasible entities}}{\text {Total number of entities}}$

The probability of getting a number between 1 and 100 which is a prime number is  

$\Rightarrow \frac{\text {Total number of prime number feasibility from } 1 \text { to } 100}{\text { Total numbers between } 1 \text { and } 100}$

$=\frac{25}{100}$

$\text{ Probability of the number between 1 and 100}=\frac{1}{4}$

Therefore, probability of getting a number which is divisible by 1 and itself  

$\Rightarrow \frac{1}{4}=0.25$