Question

find the probability of getting a number less than 4 in a single throw of a dice​

Answer 1

The probability of getting a number less than 4 in a single throw of a dice is 1/2

Given :

A dice is thrown once

To find :

The probability of getting a number less than 4

Solution :

Step 1 of 3 :

Find total number of possible outcomes

Here it is given that a dice is thrown once

So possible outcomes are 1 , 2 , 3 , 4 , 5 , 6

The total number of possible outcomes = 6

Step 2 of 3 :

Find total number of possible outcomes for the event

Let A be the event that of getting a number less than 4

Then possible outcomes for the event A are 1 , 2 , 3

So total number of possible outcomes for the event A is 3

Step 3 of 3 :

Find the probability

Hence the required probability

= P(A)

$\displaystyle \sf{ = \frac{Number \: of \: favourable \: cases \: to \: the \: event \: A }{Total \: number \: of \: possible \: outcomes }}$

$\displaystyle \sf{ = \frac{3}{6} }$

$\displaystyle \sf{ = \frac{1}{2} }$

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Answer 2

Answer:

The probability of getting a number less than 4 in a single throw of a dice is 1/2. ​

Step-by-step explanation:

When a die is thrown, the possible outcomes are ( 1,2,3,4,5,6).

Number of possible outcomes= n(S) = 6

P(E)= Number of favorable outcomes/ Number of possible outcomes

Let E be the event of getting a number less than 4.

Outcomes favorable to E are (1,2,3)

Number of favorable outcomes = n(E) = 3

P(E) = n(S)/n(E) = 3/6=1/2

Hence the probability of getting a number less than 4 is 1/2.