Question

find the probability of getting a prime number from the first 20 natural numbers.​

Answer 1

Step-by-step explanation:

Given:

n(a) = 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20.

n(s) = 20.

therefore,

the probability of getting

a prime number from first 20 natural number p(e) =

$\frac{n(a)}{n(s)}$

p(e) =

$\frac{1 \: 2 \: 3 \: 5 \: 7 \: 11 \: 13 \: 17 \: 19}{20}$

p(e) =

$\frac{9}{20}$