Question

Find the probability of getting a prime number in a single throw of dice​

Answer 1

No. of prime numbers in a regular dice = 3

Total no. of 'numbers' present = 6

We know, P(E) = (No. of favourable outcomes - of E)/(Total no. of outcomes) {Empirical probability}

∴ P(Prime No.) = 3/6 = 0.5

More:-

The concept of probability was introduced by Pierre de Fermat along with Blaise Pascal.

• If P(E) is a probability of a certain event, then $P(E^C)$ or $P( \overline{E})$ will be known as complementary event.
• $P(E) + P(E^C) = unity$.