find the probability of getting a sum of 7 or 8 in throwing a die twice
Answers
Probability of getting sum of 7 or 8 is when the dice is thrown twice.
Solution:
The total possibility of numbers when throwing 2 dices is used as Sample Space for the problem:
Possible combination of 2 dices casted is {1,2,3,4,5,6} and {1,2,3,4,5,6}
Possibility for sum 7 on the 2 dies casted = 6 [{1,6}{2,5}{3,4}{4,3}{5,2}{6,1}]
Possibility for sum 8 on the 2 dies casted = 5 [{2,6}{3,5}{4,4}{5,3}{6,2}]
The possibility of getting 7 or 8 when the dies are casted = 6+5 = 11
Total probability of getting a sum of 7 or 8 = .
The probability of getting a sum of 7 or 8 in throwing a die twice is
Step-by-step explanation:
Given Data
Total number of outcomes n(S) = 36
To find the probability of getting a sum of 7 or 8 in throwing a die twice
Possibilities in getting a sum of 7 = (1,6) , (2,5) , (3,4) , (4,3) , (5,2) and (6,1)
Number of possibilities in getting a sum of 7, n(A) = 6
Possibilities in getting a sum of 8 = (2,6) , (3,5) , (4,4) , (5,3) and (6,2)
Number of possibilities in getting a sum of 8, n(B) = 5
Probability of getting sum of 7 or 8 = P(A) + P(B)
Therefore the probability of getting sum of 7 or 8 in throwing a die twice is
To Learn More ...
1) A die is thrown twice. what is the probability of the events (getting a doublet)
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2) A die is thrown twice. What is the probability that (i) 5 will not come up either time? (ii) 5 will come up at least once?
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