Question

find the probability of getting a sum of 9 when two dice are​

Answer 1

Explanation:

In two throws of a die, n(S) = (6 x 6) = 36.

Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.

P(E) =n(E)/n(S)=4/36=1/9.

=1/9

Answer 2

$the \: proabability \: of \: getting \: a \: sum \: of \: 9 = \frac{2}{6}$