Question

find the probability of getting an even number and a multiple of 3​

Answer 1

Answer:

Question is incomplete

Step-by-step explanation:

Answer 2

Answer:

Let A be an event of getting even numbers and

Let B be an event of getting number which is a multiple of 3

S = {1, 2, 3, 4, 5, 6} , |S| = 6

A = {2, 4, 6}, |A| = 3

B = {3, 6}, |B| = 2

Probability of getting the event A or B is P(A U B)

P(AUB) = P(A) + P(B) - P(A^B) [ read ^ as intersection]

Both A and B are independent events so the 3rd shall be 0

therefore, P(AUB) = P(A) + P(B)

P(A) = |A| / |S| = 3/6 = 1/2

P(B) = |B| / |S| = 2/6 = 1/3

P(AUB) = 1/2 + 1/3 = 0.83 or 83%