Find the probability of getting an odd difference in throwing a die twice.
Answers
Answered by
2
My answer is 18 upon 36.
Is it correct?
Answered by
0
Answer:
Step-by-step explanation:
nS(6)-number of outcomes
Favorable outcomes-(1,3,5)
P(getting a odd difference)- number of favorable outcomes/number of outcomes
=3/6
=1/2
Plz make it the brainliest answer
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