Math, asked by chiblokesh, 8 months ago

find the probability of getting an odd number when a dice is rolled ?(pls solve this urgently pls )​

Answers

Answered by shabbir825
4

Answer:

Many of the examples we consider will involve games (and gambling). There are two reasons for this: such games typically involve very strict rules, which make mathematical computations much easier; and the study of probability as a branch of mathematics first came into being when noblemen hire mathematicians to help give them an edge in their games of chance.

You are likely familiar with a standard six-sided die, a small cube with 1, 2, 3, 4, 5, or 6 dots on each side. We call a die "fair" if each side has an equal likelihood of turning up. In this situation, rolling a six-sided has 6 outcomes, each of which is equally likely, so we can define the probability of an event (such as rolling a 3 or rolling an odd number) as the ratio of favorable outcomes to possible outcomes: the probability of rolling a 3 is

1

6

and the probability of rolling an odd number is

3

6

=

1

2

(because three of the possible outcome are odd numbers).

We often write P(roll a 3) =

1

6

to stand for "the probability that you roll a 3 is equal to 1/6" where P(E) means the probability that event E occurs. (This is like function notation in algebra: the parentheses do not mean multiplying P times E in this situation.) We might also right P(3) instead of P(roll a 3) as long as the context is clear (that we're rolling a single six-sided die and looking to get a 3.)

In practice, even if a die is absolutely fair (and few dice truly are), we might roll the die 12 times (say) and not get any threes. Or we might get 4 threes instead of the 2 threes we'd expect to get. But if rolled the dice a million times, or a billion times, we would expect the percentage of rolls resulting in threes would eventually settle in on

1

6

, or 16.67%, as in this graph:

which shows the "running percentage" of threes after 1, 2, 3, 4,...10, 11, 12,...100, 101, 102,... etc. rolls. Notice that the horizontal scale is logarithmic (it jumps by powers of 10) and that the percentage doesn't settle down to be very close to 0.1667 until well after 1,000 rolls.

This is a demonstration of the Law of Large Numbers, which says that the observed percentage of favorable outcomes in a finite number of trials (n) will approach the theoretical probability of that outcome as n gets very large. The only problem is that this law doesn't define what "very large" means: it could be 1,000 or 1,000,000 or 1,000,000,000 or even more.

hope it helped u

Answered by bulusupadmasri
11

Answer:

Step-by-step explanation:

No. Of odd numbers are 3....I.e,1,3,5

No. Of total incomes are 6.

So probability of getting an odd no. Is equal to 3/6=1/2.

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