Find the probability of getting at least two heads when four coins are tossed
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This is a simple case of the Binomial Distribution, with n=4 and p=.5
The probability mass function of the Binomial Distribution is
nCx.(p^x)(1-p)^(n-x), C here is the combination function.
Using this function, the probability of getting xnumber of heads is:
(X)
4 heads 0 tails = 1/16
3 heads 1 tails = 4/16
2 heads 2 tails = 6/16
1 head 3 tails = 4/16
0 head 4 tails = 1/16
Cheers!
The probability mass function of the Binomial Distribution is
nCx.(p^x)(1-p)^(n-x), C here is the combination function.
Using this function, the probability of getting xnumber of heads is:
(X)
4 heads 0 tails = 1/16
3 heads 1 tails = 4/16
2 heads 2 tails = 6/16
1 head 3 tails = 4/16
0 head 4 tails = 1/16
Cheers!
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