Question

Find the probability of getting atleast one head in a throw of two coins.

Answer 1

If two coins are thrown then total outcomes =hh ,ht ,th ,tt.
no of total outcomes =4.
no of at least one head = 3.
probability of at least one head = no of at least one tail /total no of observations.
= 3 /4.

Answer 2

Sample space = {HH,HT,TH,TT}
n(S) = 4
Event(getting atleast one head) = {HH,HT,TH}
n(E) = 3
Probability
P(E) = n(E)/n(S) = 3/4