Question

find the probability of getting exactly 2 heads in tossing a fair coin 4 times

Answer 1

Heya friend,

Here's your answer,



Let's create a sample space first..



               H            T

H          (H,H)      (T,H)


T          (H,T)       (T,T)

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          (H,H)          (T,H)          (H,T)           (T,T)

H     (H,H,H)       (T,H,H)       (H,T,H)        (T,T,H)

T     (H,H,T)        (T,H,T)       (H,T,T)         (T,T,T)      

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      (H,H,H)     (T,H,H)    (H,T,H)     (T,T,H)     (H,H,T)      (T,H,T)     (H,T,T)      (T,T,T)


H   (H,H,H,H) (T,H,H,H) (H,T,H,H) (T,T,H,H) (H,H,T,H)   (T,H,T,H)  (H,T,T,H)   (T,T,T,H)


T   (H,H,H,T)  (T,H,H,T) (H,T,H,T) (T,T,H,T)  (H,H,T,T)   (T,H,T,T),  (H,T,T,T),  (T,T,T,T)


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Hence, the total number of outcomes = 16.


Probability of exactly 2 heads = 6/16
                                           
                                              = 3/8

                                             = 0.375


Hope this helps!!!

Answer 2

2\4
1\2 is the probably of head

I hope this will help you
By Devansh