Question

Find the probability of getting exactly one head when two coins are tossed?

Answer 1

GIVEN:

• Two coins are tossed.

TO FIND:

• The probability of getting : One head.

CONCEPT USED:

• Probability = The number of ways of achieving success. the total number of possible outcomes.
• Formulae = Favorable outcomes / Total number of outcomes

SOLUTION:

When two different coins are tossed randomly, the sample space is given by :

S = {HH, HT, TH, TT}

The possible outcome may be = 2² or 4

Therefore, n(S) = 4.

• Exactly one Head :

↪ Probability = Favorable outcomes/ Total outcomes

↪ Probability of Getting exactly one Head = 2/4 OR ½

Hence, The probability of getting exactly one head when two coins are tosssed is ½

Answer 2

Given ,

When two coins are tossed :

• Sample space (S) = {HT , HH , TT , TH}

We know that ,

$\fbox{Probability = \frac{Number \: of \: favorable \: outcomes }{Total \: number \: of \: outcomes} </p><p></p><p> }$

Thus ,

$\sf \mapsto P(one \: head) = \frac{2}{4} \\ \\ \sf \mapsto P(one \: head) = \frac{1}{2}$

Therefore , the probability of getting exactly one head , when two coins are tossed is 1/2