Question

Find the probability of getting sum of two numbers ,less than 3 and more than 11,when the pair of distinct dice is thrown together.


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Answer 1

Answer:

$\dfrac{1}{18}$

Step-by-step explanation:

Given-----> we throw two dices and add the numbers we get on dices

To find----> probability of getting sum of numbers less than 3 or greater than 11

Concept used---->

1) Sum of nubers on two dices can be 2, 3, 4,.............., 12

So sum of numbers on two dice less than 3 is can only be 2 and sum of numbers greater than 11 is only 12

2)

$probability \: = \dfrac{number \: of \: favorable \: cases}{total \: number \: of \: cases}$

Solution---->

Number of ways to throw one dice = 6

Number of ways to throw two dice = 6×6=36

Number of ways to get sum of nubers on two dices less than 3 is only one which is when we get one on both dice ie ( 1 , 1 )

Nuber of ways to gey sum of numbers on two dice greater than 11 is only one when on both dice we get six ie ( 6,6 )

So nuber of ways to get sum of numbers on dice less than 3 or greatet than 11 is 2

now

$required \: probability \: = \dfrac{number \:of \: favourable \: cases }{total \: number \:of \: cases } \\ = \dfrac{2}{36} \\ = \dfrac{1}{18}$

Answer 2

Answer:

probability would be 2/36=1/18

Step-by-step explanation:

hope it helps...