Question

Find the probability of getting the difference as 1 when two dice are thrown simultaneously.

please solve it step by step... and please solve it as fast as possible!

Answer 1

Given that total number of dice rolled = 2.

We have n(S) = 6 * 6

                       = 36.


Let A be the event of getting the difference as 1.

n(A) = {1,2},{2,3},{3,4},{4,5},{5,6},{2,1},{3,2},{4,3},{5,4},{6,5}
 
        = 10.


Therefore, the Required probability P(A) = n(A)/n(S)

                                                                    = 10/36

                                                                    = 5/18.



Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks