Question

find the probability of getting three head if we tossed 10 balaced coin

​

Answer 1

Step-by-step explanation:

step 1 Find the total possible events of sample space S

S = {HHHHHHHHHH, HHHHHHHHHT, HHHHHHHHTH, HHHHHHHHTT, HHHHHHHTHH, HHHHHHHTHT, HHHHHHHTTH, HHHHHHHTTT, HHHHHHTHHH, HHHHHHTHHT, . . . . . . ,TTTTTTTHTT, TTTTTTTTHH, TTTTTTTTHT, TTTTTTTTTH, TTTTTTTTTT}

S = 1024

step 2 Find the expected or successful events A

A = {HHHHHHHHHH, HHHHHHHHHT, HHHHHHHHTH, HHHHHHHHTT, HHHHHHHTHH, HHHHHHHTHT, HHHHHHHTTH, HHHHHHHTTT, HHHHHHTHHH, HHHHHHTHHT, . . . . . . ,TTTTTTHHHH, TTTTTTHHHT, TTTTTTHHTH, TTTTTTHTHH, TTTTTTTHHH}

A = 968

step 3 Find the probability

P(A) =Successful Events

Total Events of Sample Space

=968

1024

= 0.95

P(A) = 0.95

0.95 is the probability of getting 3 Heads in 10 tosses.

Answer 2

Answer:

for 3 Heads in 10 Coin Flips

Atleast 3 Heads Exactly 3 Heads

Probability P(A) 0.95 0.12