Find the probability of having 53 Friday in a year.
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Answered by
1
Answer:
Here is your Answer .
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Step-by-step explanation:
27
Here, favourable outcomes will count only those cases out of all the possible outcomes in which there is Friday occurring i.e., Thursday and Friday, Friday and Saturday only. Probability of getting 53 Fridays in a leap year=27.
Answered by
1
Answer:
There are 366 in a that is to more than52 full weeks 52×7+2=366
Therefore now for the least 2days,there could be7 possibilities all equally likely
There are:
(Monday,Tuesday),(Tuesday, Wednesday), Wednesday,Thursday),(Thursday,Friday),Friday, Saturday),Saturday,Sunday), Sunday,Monday)
There are 2 cases out of the seven cases above such that there is an extra Friday
Therefore the required probability here is 2/7.
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