Question

Find the probability of having 53 Sunday in a leap year

Answer 1

Answer:

In a non-leap year there will be 52 Sundays and 1day will be left. This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, friday, Saturday, Sunday. Of these total 7 outcomes, the favourable outcomes are 1. Hence the probability of getting 53 sundays = 1 / 7

Answer 2

Answer:

Your answer is:

n(A) = 53

n(s)= 366

P(A) = n(a)/n(s)

P(A)= 53/366

Step-by-step explanation:

I hope it will help you!