Question

Find the probability of having 53 sundays in a non leap year

Answer 1

We know that year has 365 days

365÷7=52+1day

52 weeks and a day

This s={monday, Tuesday, wednesday, Thursday, friday, Saturday, sunday}

n(S)=7

Let A be event of getting sunday

n(A)=1

Therefore probability of getting 53 Sundays=1/7