Question

Find the probability of having 53 Sundays in (I) a leap year.
(2) a non leap year.

Answer 1

The two odd days can be ;

{Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.

So there are 7 possibilities out of which 2 have a Sunday.

So the probability of 53 Sundays in a leap year is.

A non-leap year has 365 days or 52 weeks and 1 odd day.