Question

Find the probability of having 53 thursdays in a leap year.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The probability of having 53 thursdays in a leap year is 2/7

Given :

53 thursdays in a leap year

To find :

The probability

Solution :

Step 1 of 3 :

Find total number of possible outcomes

Leap year = 366 days

366 days = 52 weeks 2 days

Now 52 weeks contains 52 thursdays

2 days is one of the below

( Sunday, Monday), ( Monday, Tuesday), (Tuesday, Wednesday), ( Wednesday, Thursday), ( Thursday, Friday), ( Friday, Saturday ), (Saturday, Sunday)

So the total number of possible outcomes = 7

Step 2 of 3 :

Find total number of possible outcomes for the event

Let A be the event that of getting 53 thursdays in a leap year

So the total event points for the event A is ( Wednesday, Thursday), ( Thursday, Friday)

So the total number of possible outcomes for the event A is 2

Step 3 of 3 :

Find the probability

Hence the required probability

= P(A)

$\displaystyle \sf{ = \frac{Number \: of \: favourable \: cases \: to \: the \: event \: A }{Total \: number \: of \: possible \: outcomes }}$

$\displaystyle \sf{ = \frac{2}{7} }$

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