Math, asked by samruddhichordiya03, 1 year ago

Find the probability of having 53 Wednesdays in a leap year.
13???

Answers

Answered by irfan122

1

Answer:

$\frac{2}{7}$

is the answer

Answered by ketubh

0

Step-by-step explanation:

its 2upon 7. in a leap year the probability of 53 Wednesdays is 2 upon 7 by this method

Attachments:

Previous Question

Next Question

Similar questions

English, 5 months ago

Can you see green image of an object in the mirror in a completely darkroom? Why?

Economy, 5 months ago

When price falls with increase in output the TR is (1) (a) AR = MR (b) AR > MR (c) MR > AR (d) AR = TR...

English, 5 months ago

How many of them forget to shut the front door when leaving the house? (scarcely ) more hardly surely plenty formerly ...

Chemistry, 1 year ago

blue crystal of copper sulphate are heated...

Physics, 1 year ago

Name the nerve which carries electrical impulses from the cochleo of ear to brain ...

English, 1 year ago

You want to sell your bike is you are going abroad. Staff a suitable advertisement be publish in news paper...

India Languages, 1 year ago

What is third proportion of 25 and 75...

Math, 1 year ago

In the given figure alongside ,squares ABDE and AFGC are drawn on the side AB and the hypotenuse AC of the right triangle ABC.If BH is perpendicular to FG,prove that:1)Area of the square ABDE=Area of the rectangle ARHF.With proper solution have to be given for this question otherwise he will not get 25 points and will not be marked in brainliest by me.