find the probability of having both 53 Fridays and 53 Thursdays in a leap year
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Answered by
36
Answer:
Since Leap year have
=> 3/7
For a leap year to have either 53 Thursday or 53 Friday, it must have them in the two days. 52 weeks and 2 days. So we can have any of these combinations, a Wednesday and Thursday, a Thursday and Friday, a Friday and Saturday. Thus the probability is 3/7
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