Math, asked by kurapatisai1683, 8 months ago

Find the probability of having not 53 Thursdays and 53 Thursdays in a leap year and non-leap year selected at random.

Answers

Answered by Pruthvipabale049
1

Answer:

hhjouhgda. m

Step-by-step explanation:

1#&$:(((you 78941

Answered by jasminekaur12
2

Therefore possibilities 3, 4, and 5 from above will have either 53 Thursdays or 53 Fridays. So 3 possibilities out of 7: the answer is 3/7 or about 43% probability that a leap year selected at random will have either 53 Thursdays or 53 Fridays.

Similar questions