Find the probability of having not 53 Thursdays and 53 Thursdays in a leap year and non-leap year selected at random.
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1
Answer:
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Step-by-step explanation:
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2
Therefore possibilities 3, 4, and 5 from above will have either 53 Thursdays or 53 Fridays. So 3 possibilities out of 7: the answer is 3/7 or about 43% probability that a leap year selected at random will have either 53 Thursdays or 53 Fridays.
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