find the probability of non defective bulbs
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Step-by-step explanation:
There are total 600 electric bulbs.
Sample Space , S = (600)
No of defective bulbs = 12
No of non-defective bulbs = 600-12=588
Let A be the event that the bulb taken out is a non-defective bulb
A = {588}
n(A)= 588
P(A)= n(A)/n(S)=588/600= 49/50
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