Question

Find the probability of not getting a 7 or 11 total on either of two tosses of a pair of fair dice

Answer 1

Answer:

Probability of getting a sum of 7 when a pair of fair dice tossed = 6/36

Step-by-step explanation:

This is because (1,6) (2,5) (3,4) (4,3) (5,2) and (6,1) are favourable outcomes  

Total number of possible outcomes = 6^2 = 36  

Probability of getting a sum of 11 when a pair of fair dice tossed = 2/36  

because (5,6) and (6,5) are favourable outcomes  

Probability of getting a sum of 7 or 11 on first toss =  

6/36 + 2/36 = 8/36  

Probability of getting a sum of 7 or 11 on second toss = 8/36  

Probability of getting 7 or 11 on either of two tosses =  

8/36 + 8/36 = 16/36  

PROBABILITY OF NOT GETTING 7 OR 11 ON EITHER OF  

TWO TOSSES OF A PAIR OF DICE = 1 - 16/36 = 20/36