Find the probability of obtaining three heads on tossing three coins
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When 3 unbiased coins are tossed once. And, therefore, n(S) = 8. and, therefore, n(E1) = 1. Therefore, P(getting all heads) = P(E1) = n(E1)/n(S) = 1/8.
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1/8
sample space- 2³ -8
probability=1/8
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